R the mean acting radius of the caliper on the disc. Its value is well computed by the product T=2*F*µ*R with F-Īpplied force by the hydraulic cylinder/ µ the friction between disc and brake and Φ you can compute T= E/ Φ take care to have Φ in radian and NOT in degrees!Ĩ- Now you know the torque you must apply toīreak your cart. ε= a/r with a= above linear acceleration = Ω=ε*t ε being the angular acceleration of the rear wheels. The working done by such a moment is W= T*Φ=E=M*v²/2Īngle of rotation for the breaking time Φ=ω*t = velocity *time or Φ=ε*t²/2 with Placed at the rear axis so that in 6 the whole kinetic energy will be The problem can be set this way: how big should be a resistance torque The vehicle speed figures at the square so in the first step it has to be This period the rolling resistance is still active but decreases rapidly since The kinetic energy the vehicle has when the process is started. That you should consider a breaking length of 7*(65/50) ^ 2=12.Ī constant breaking resistance you have the equation:Ī*t^2/2 with a= deceleration = 0.3*2.25=0.675 ħ- Breaking is equivalent to the reduction of This MUST be taken into consideration.Ħ- On a dry ground you can accept that fromĥ0km/h to zero a length of at least 7m is required. Structure inertia increases the load on front wheels and decreases the part of On the wheels is not any more the static one you considered. Instance you break too much on a wet or icy ground.ĥ- When you break the distribution of loads No case the sliding makes your vehicle uncontrollable. Go-cart for young men this limit can be multiplied by about 2-2.5.Ĥ- Your breaking moment should be so that in You can consider values as 0.03 (on asphalt) and 0.2-0.4 on solid sand.īody should not have to support more than 0.3-0.4g as acceleration. Therefore the vehicle will stop in 0.06second over a distance of 1.38feet.ġ- The coefficient of 0.7 is the sliding coefficient but not the rolling one.īox" the rolling resistance can be computed with the equation: Rear calipers can be found by following formula:Įach caliper to the center of each moving axle.Įntire length of the axle we can find the forces that are acting on each tire. Master cylinder can be calculated as follow: Therefore the vehicle would stop in 0.056 second over a distance of 1.159 * the negative sign indicates deceleration.
Normally this value varies between (0.1 to 0.9) depending on environment. N (rear) = (319.67 * 32.17 * 0.100) = 10283.8 lbfįorces acting on rear tires the frictional forces rear can be calculated asįriction was assumed-to be 0.7 for our tires according to Stratus Karts. Tire caused by the weight of the go kart and driver, lbfįorces on front and rear tires are respectively: as i am a rookie therefore i need someone experience to check my calculation. i am in braking team therefore i did braking calculations accordingly.
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